What is the Kinetic Energy of the Recoil Electron?

  • Thread starter Thread starter Binxie08
  • Start date Start date
  • Tags Tags
    Photon Wavelength
Binxie08
Messages
3
Reaction score
0
Ok so i got this problem in my physics textbook and I'm just struggling with the last part, please help

X-rays are detected at a scattering angle of 163 and have a wavelength of 0.1867 nm. Find (a) the wavelength of an incident photon, (b) the energy of an incident photon, (c) the energy of a scattered photon and (d) the kinetic energy of the recoil electron



Okie the equations i used are the compton shift equation to determine the wavelength of the incident photon (the x-ray) and also used the equation for energy of a photon to calculate the energy of the incident and scattered photon...but then i got stuck and don't know how to calculate the kinetic energy of the recoil electron:rolleyes:



I got the incident wavelength to be 4.75 x 10^-12 m, the energy of the incident photon to be 1.09 x 10^-15 J and the energy for the scattered photon to be 1.06 x 10^-15 J. I just need to know how to calculate the kinetic energy of the recoil electron

Thanks
 
Physics news on Phys.org
You know the energy of the initial photon, and the enegery of the final photon.

Now use the conservation of energy to calculate how much energy the electron will have, and from that the kinetic energy via the usual formula.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top