What is the launch speed required for a skier to reach a height of 11.7 m

[Joules23]

The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply upward at the end. The sharp upward slope launches them into the air, where they perform acrobatic maneuvers. In the women's competition, the end of a typical launch ramp is directed 63° above the horizontal. With this launch angle, a skier attains a height of 11.7 m above the end of the ramp. What is the skier's launch speed?

i don't know where to begin with this since so little info is given,

 

[NateTG]

This is mostly a 1-D problem.

 

[Joules23]

ok, i have the 3 sides of the traingle, but i do now know what to do with them, 13.13, 11.7, 5.96

 

[NateTG]

Here's a slightly easier problem you could solve first:
If I throw a ball straight up, how fast do I need to throw it so that it goes up 11.7 meters?

 

[Joules23]

EDIT: u are right it is too high.. 15.14m/s is the right one i think

 

[NateTG]

That number seems a bit high ...

Now, let's say that I throw the ball at a 45 degree angle with horizontal instead of straight up - how fast do I have to throw it?

 

[Joules23]

i have no idea

 

[Joules23]

can anyone PLEASE help, i have the answer(16.99), i just don't know how to get the answer

 

[NateTG]

What's the vertical component of the velocity of the ball when I throw it?

 

[Joules23]

10.7m/s ??

 

[NateTG]

10.7m/s ??

It would only go up about 5m if that was the vertical component.

 

[Joules23]

Vy of the ball at 45degrees or Vy of the ball thrown straight up? wow if every problem is going to take me this long i think ill be done next month
can you give me a forumla or something for the actual problem

 

[Joules23]

anyone? I am completely lost

 

[NateTG]

Vy of the ball at 45degrees or Vy of the ball thrown straight up? wow if every problem is going to take me this long i think ill be done next month
can you give me a forumla or something for the actual problem

The way I would do this problem is:
1. Figure out the vertical component of the skiers velocity at the end of the ramp.
2. Use trig to determine the total velocity.

 

[Joules23]

How would i find the vertical component of the skiers velocity, when it does not give the velocity

IS 11.7 the vertical component?

 

[NateTG]

The horizontal and vertical components are independant.