What is the magnetic flux through the prism's right side?

AI Thread Summary
The discussion focuses on calculating the magnetic flux through the hypotenuse of a prism given specific dimensions and a magnetic field strength. The participant calculated the hypotenuse length as 1.22 meters and used the formula Flux = BAcos(theta) to find the flux value. They derived a flux of 2.6432 Wb but received feedback that their answer was incorrect, leading to speculation about significant figures. Another participant confirmed the initial calculation was correct, suggesting the answer should be 0.8164 Wb, indicating a potential misunderstanding in the application of the formula or angles. The conversation emphasizes the importance of accuracy in calculations and understanding the geometric relationships involved.
Se Hoon Park
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Homework Statement


e5L8fBt.jpg

Now, ignore the lengths given in the photo.

Height (y) = .640 meters
Length (z) = 1.18 meters
Base (x) = .320 meters
Magnetic Field (B) = 3.5 Teslas in the +X direction

Homework Equations


The problem is to find the magnetic flux through the surface of the prism that is the hypotenuse (side aedf). So, the equation for this should be Flux = BAcos(theta)

The Attempt at a Solution


Well, working out the problem, I figured out the length of the hypotenuse is 1.22m because of pythagorean theorem. So, B*A is simply

(1.22)(.640)(3.5T)=2.7328

Now, theta is the angle that is between the magnetic field and the orthogonal of the surface itself. This angle should be the same as the angle between the base of the triangle and the hypotenuse. So this ratio is (1.18/1.22). So the flux should be

2.7328 * (1.18/1.22) = 2.6432 Wb

But the answer keeps spitting out as wrong! What did I do wrong here?
 
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Perhaps it requires the correct number of significant figures.
good luck
 
I got 0.8164Wb.
If that checks I can give you hints as to how I derived it.
Se Hoon Park said:

Homework Statement


e5L8fBt.jpg

Now, ignore the lengths given in the photo.

Height (y) = .640 meters
Length (z) = 1.18 meters
Base (x) = .320 meters
Magnetic Field (B) = 3.5 Teslas in the +X direction

Homework Equations


The problem is to find the magnetic flux through the surface of the prism that is the hypotenuse (side aedf). So, the equation for this should be Flux = BAcos(theta)

The Attempt at a Solution


Well, working out the problem, I figured out the length of the hypotenuse is 1.22m because of pythagorean theorem. So, B*A is simply

(1.22)(.640)(3.5T)=2.7328

Now, theta is the angle that is between the magnetic field and the orthogonal of the surface itself. This angle should be the same as the angle between the base of the triangle and the hypotenuse. So this ratio is (1.18/1.22). So the flux should be

2.7328 * (1.18/1.22) = 2.6432 Wb

But the answer keeps spitting out as wrong! What did I do wrong here?
Your answer is correct. Guaranteed!
 
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