What is the Magnitude of F2 in a Hinged Beam Torque Problem?

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In the hinged beam torque problem, the massless bar is inclined at 28.0° and is in static equilibrium under the influence of forces F1 and F2. The equations for forces and torques indicate that the sum must equal zero, leading to the calculation of F2. The derived formula for F2 is F2 = F1L2sinθ/(L2cosθ), resulting in a value of approximately 7.17 N. A question arises regarding whether the torque produced by F1 is dependent on L2 instead of L1. The discussion emphasizes the importance of correctly identifying the lever arm for torque calculations.
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Homework Statement



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The massless bar, hinged at A, is inclined at an angle θ = 28.0° and subjected to horizontal and vertical forces F1 and F2, as shown. If L1 = 2.30 m, L2 = 1.00 m, F1 = 31 N, and the beam is in static equilibrium, what is the magnitude of F2?


Homework Equations



T=Fr

The Attempt at a Solution



sum of forces and torques must be null
forces
F1+Rx=0
F2+Ry=0
torques
F2L2cosθ-F1L2sinθ=0
F2=F1L2sinθ/(L2cosθ)
F2=31*1*sin28/(2.30*cos28)=7.17 N
 
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Are you sure the torque produced by F1 about point A depends on L2 and not L1?
 
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