What is the magnitude of the torque exerted on the loop?

AI Thread Summary
The discussion focuses on calculating the torque exerted on a rectangular loop of wire in a magnetic field. The loop has 101 turns, dimensions of 0.97m by 0.23m, and is positioned at a 70-degree angle in a uniform magnetic field of 0.62 T with a current of 3.1 A. Participants clarify the correct application of the torque formula T = NIABsin(θ), emphasizing the need to include the number of turns in the calculation. The correct torque calculation is confirmed as approximately 40.7 N*m using the provided values. The conversation highlights the importance of ensuring all parameters are correctly included in the formula for accurate results.
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A rectangular loop consists of 101 closely wrapped turns of wire and has dimnesions .97m by .23m. The loop is hinged along the y-axis and its plane makes an angle of 70 degrees with the x axis.

A uniform magnetic field of .62 T is directed along the x-axis and the current in the loop is 3.1 A in the downward direction.

What is the magnitude of the torque exerted on the loop?

okay so for this problem I tried to apply the T=NIABsin() but that doesn't work...how do I go about this problem?

I have the radius=27.2
I can get the area by multiplying the dimensions
I have the current, I = 40 A
The Mag Field B=4.07 T
and 33 degrees

what do I do ?
 
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Values given by you do not match with the given problem. In the problem the rectangular loop is given. From where did you get the radius?
 


oh sorry! that was not part of the problem. There is no radius given
 


Show your calculations.
 


okay so what I inititally did was T=NIABsin()

so I assumed there was only one loop so I plugged in T= (1)(3.1A)(.97*.23)sin(70)

and I got T=.4029385043

but that is not correct so what am I doing wrong? Am I just using the totally wrong equation? What am I missing?
 


You didn't multiply the number of turns in the coil.
 


why would I multiply the number of turns in the coil?

Also, I did that but I still did not get the right answer.

(101)(3.1 A)(.2231m^2)(.62T)sin(70)= 40.6967 N*m
 


is it correct that I use the equation T=NIABsin() ?

where N= 101 turns
I = 3.1 A
A= .97m * .23m
B= 0.62T
and sin()= sin(70) ??
 
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