What Is the Mass of the Second Ice Skater?

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The discussion revolves around calculating the mass of the second ice skater after they push off from each other. The first skater has a mass of 60 kg and moves at a speed of 0.61 m/s, while the second skater moves at 0.8 m/s. Initial attempts to use kinetic energy equations were incorrect, as the conservation of momentum should be applied instead. The correct momentum equation is m1v1 = m2v2, which leads to the accurate calculation of the second skater's mass. The importance of using momentum conservation over energy conservation in this scenario is emphasized.
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Homework Statement



Two ice skaters stand at rest in the center of an ice rink. When they push off one another, the 60 kg skater acquires a speed of .61 m/s. If the speed of the other skater is .8m/s what is this skater's mass?

Homework Equations



explosion- pi=pf

The Attempt at a Solution



1/2m1v1^2=m2v2^2
1/2(60)(.61^2)=m2(.8^2)
11.16=m2(.64)
m2=17.43 but it said this was wrong

but then i got a really big number which doesn't seem right
 
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Recheck your formulas. What's the formula for the momentum of a moving body?
 
p=mv?
 
eagles12 said:
p=mv?
Is that a guess?
 
so do i do m1v1=m2v2 instead of squaring the velocities
 
got it! thanks
 
yes, that's right man. Its simply conservation of momentum.
 
There is NO "conservation of energy" (which is what you were trying to use first) because the "explosion" (push) adds energy to the system.
 
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