What is the maximum charge that can be put on a charged aluminum sphere?

AI Thread Summary
Charging an aluminum sphere to hold a negative charge of 8 Coulombs is impractical due to the dielectric breakdown of air, which occurs at around 1 MV/m. To avoid breakdown, the sphere would need to be approximately 268 meters in radius, making it unfeasible. A van der Graaff generator could theoretically charge the sphere, but the required size and charge are excessive. The discussion shifts to exploring the maximum charge for a smaller sphere, like one the size of a basketball, indicating a need for more practical solutions. Overall, achieving such high charges on small conductive objects poses significant challenges due to physical limitations.
Frogmansailor
Messages
2
Reaction score
0
I am doing some conceptual design, and was hoping to be able to get some answers here before I devote too much time to this.

I would like to be able to charge a piece of aluminum so that it holds a charge (negative) of 8 Coulombs. I was hoping to achieve this with something similar to a van der graaf generator, which would charge a spherical piece of aluminum which is encased in a strong insulator so that the charge is safely contained.

So my questions are:

How big would this piece of aluminum have to be?
Would a van der graaf type generator work for this application?
How fast would this conductor bleed it's charge?
What insulator would best reduce this loss of charge?

Thanks in advance
Dave
 
Physics news on Phys.org
It's not going to happen. The field at the surface of a sphere is Q/(4*pi*epsilon_0*R^2), and air breaks down at a field strength of about 1 MV/m. To put 8 Coulombs on the sphere, you'd then need a sphere of a radius of 268 m to prevent the air around it from breaking down. 8 Coulombs is a lot of charge.
 
Well the dielectric breakdown of air being so low is the reason I want to surround it with a better insulator, so that isn't accurate.

I realize 8 C is a ton of charge, I was just hopeful I guess. What would the maximum charge that one could put on a sphere about the size of a basketball then?
 
Thread 'Inducing EMF Through a Coil: Understanding Flux'
Thank you for reading my post. I can understand why a change in magnetic flux through a conducting surface would induce an emf, but how does this work when inducing an emf through a coil? How does the flux through the empty space between the wires have an effect on the electrons in the wire itself? In the image below is a coil with a magnetic field going through the space between the wires but not necessarily through the wires themselves. Thank you.
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (Second part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8. I want to understand some issues more correctly. It's a little bit difficult to understand now. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. In the page 196, in the first paragraph, the author argues as follows ...
Back
Top