What Is the Maximum Reaction Time for a Ranger to Avoid a Deer?

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The discussion focuses on calculating the maximum reaction time for a ranger to avoid hitting a deer while driving at 47 kilometers per hour, with the deer 72 meters ahead. The ranger's vehicle experiences a negative acceleration of -2.6 meters per second squared after the reaction time. The problem requires splitting the scenario into two phases: the initial reaction time where the ranger maintains speed and the subsequent braking phase. Key formulas for velocity and position as functions of time are essential for determining the maximum allowable reaction time. The calculations must consider the initial speed and the distance to ensure the ranger can stop before reaching the deer.
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Homework Statement



A ranger in a national park is driving at 47 kilometers per hour when a deer jumps onto the road 72 meters ahead the vehicle. After a reaction time of t (s), the ranger applies the brakes to produce an acceleration of -2.6 meters per second squared.

What is the maximum reaction time allowed if the ranger is to aviod hitting the deer? Answer in units of (s)


Vi = 47 km/h

d or delta x = 72

a = -2.6 m/s^2

delta t = ?
 
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keep in mind that during the reaction period delta t, the velocity of the ranger is 47 km/hafter the delta t is passed, the velocity is reduced to 0 because of the negative acceleration -2.6

You really need to split up the question in 2 parts :

1) during the delta t
2) once the delta t is finished and the ranger is actually applying the break.
So, what formula's do you know to calculate velocity and position as a function of time ?Also, pay attention to the given UNITS !

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