What is the maximum tension in the rope?

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cyspope
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Homework Statement


A 75 kg student runs at 5 m/s, grabs a rope, and swings out over a lake. He releases the rope when his velocity is zero. a) What is the angle when he releases the rope? b) What is the tension in the rope just before he releases it? c) What is the maximum tension in the rope?

Homework Equations


[tex]\Lambda[/tex]KE = [tex]\frac{1}{2}[/tex]mv[tex]_{f}[/tex][tex]^{2}[/tex] - [tex]\frac{1}{2}[/tex]mv[tex]_{o}[/tex][tex]^{2}[/tex] = mgh


The Attempt at a Solution



(75/2)*25 = 75 * 9.8 * h
h = 1.276

this is all I got.
 
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Was this the exact wording of from the question? I don't quite understand what it meant. First, you wrote when he releases the rope, his speed is 0; if so, there would not be energy transfer to the rope from the running speed of the student. Also ,have you provided all the info?