What is the Method for Finding the Magnitude of a Complex Vector?

AI Thread Summary
The discussion focuses on finding the magnitude of a complex vector defined as a = 2π K - i ρ / α^2, where ρ is a position vector and K is a Fourier space vector. The initial calculation for the magnitude squared is stated as 4π^2 K^2 + ρ^2 / α^4, using the formula (magnitude of a)^2 = a.a*. Participants emphasize the importance of showing work and understanding the underlying concepts, particularly the inner product for vectors and the magnitude for complex numbers. Clarifications are made regarding the necessity of taking the square root of the magnitude squared to obtain the final result. The conversation concludes with acknowledgment of the correct approach and the need to remember the final step of taking the square root.
David932
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Homework Statement


Let a is a complex vector given by

a = 2π K - i ρ / α^2 ,

where ρ is a two dimensional position vector and K is the corresponding two dimensional vector in the Fourier space.

In order to find magnitude of this vector, i found that it is 4π^2 K^2 + ρ^2 / α^4 .
The logic I used to get my solution is
(magnitude of a)^2 = a.a*, where * denotes the complex conjugate.

Please can someone guide me to the correct step by step solution.Thanks
 
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How can it be you have found the magnitude without going through the steps ?
What's the expression for the magnitude of a vector ?
What's the expression for the magnitude of a complex number ?
Are you aware of the PF rules and the guidelines that in fact disallow us to help you if you don't make an attempt at solution ?
 
Hi BvU i edited my question and included the formula which I used for getting the answer.
 
And the formula did its work, so what is your question ?
 
BvU said:
And the formula did its work, so what is your question ?
My question is whether the formula I used and the answer I got is correct or my logic has a conceptual mistake?
 
I think you are doing fine. For a vector you have the inner product and for a complex number you have the ##|{\bf a}|^2= {\bf aa^*}##.
(so don't forget to take the square root at the end ... :smile:)
 
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BvU said:
I think you are doing fine. For a vector you have the inner product and for a complex number you have the ##|{\bf a}|^2= {\bf aa^*}##.
(so don't forget to take the square root at the end ... :smile:)
Thanks for the reply. Yes, I should take the square root at the end.
 
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