What is the minimum thickness for destructive interference in thin film?

AI Thread Summary
The discussion focuses on calculating the minimum thickness of a thin film for destructive interference, specifically for reflected red light. The wavelength in the film is determined to be 4.81x10^-7 m with a refractive index of 1.382. The equation used is 2L = mλ, but the initial calculation of L = 2.41x10^-7 m was incorrect. Participants express confusion regarding the required phase difference for destructive interference and the correct value of 'm' to use in the equation. Clarification on the complete problem statement and scoring guidelines is sought to resolve the confusion.
TwoEyedHuman
Messages
4
Reaction score
0
1. Calculate the minimum thickness of the film for which the intensity of the reflected red ray is near zero.
(This is AP Physics B 2010 (c)ii.)
I found the wavelength in the film to be 4.81x10-7 m
nf=1.382. 2L=mλ (destructive interference)

The Attempt at a Solution


My first attempt yielded a result of L=2.41x10-7 m
That was using the equation given. I checked the result in the scoring guideline, and it was wrong. I read the explanation, but I was confused by it and didn't want to write down an answer I didn't understand.
 
Physics news on Phys.org
Can you state the complete problem.
 
TwoEyedHuman said:
2. 2L=mλ (destructive interference)
What phase difference is required for destructive interference? What value of 'm' must you use in this equation?
 
Doc Al said:
What phase difference is required for destructive interference? What value of 'm' must you use in this equation?

That is where I get confused.
 
TwoEyedHuman said:
That is where I get confused.
Well, for two rays to destructively interfere--cancel out--what must be their phase difference?
 
Back
Top