What is the minimum work needed to push a car

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To push a 1025 kg car 200 m up a 17.5° incline without friction, the minimum work required is calculated as 604,117.9512 J. When friction is considered with a coefficient of 0.40, the work done must account for both gravitational potential energy and frictional forces. The work-energy theorem states that the total work done equals the change in kinetic energy plus the change in potential energy and the work done against friction. In the scenario without friction, the change in kinetic energy is zero, simplifying the calculation. Understanding these principles is essential for determining the minimum work needed in both scenarios.
bosox3790
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What is the minimum work needed to push a 1025 kg car 200 m up along a 17.5° incline?

(a) Ignore friction.
I got 604117.9512J
(b) Assume the effective coefficient of friction retarding the car is 0.40?
how do I get this one?
 
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for a) what does work do? What aspect of the car does it change? How do you calculate the work done then?
 
Do I need to know Work in this case?
 
bosox3790 said:
Do I need to know Work in this case?
you can calculate work

work changes the energy
 
Use the work-energy theorem:
W= \Delta K + \Delta U + |W_{fric}|
To find the minimum work, push the block slowly so that \Delta K=0. In (a), W_fric = 0. What is W_fric in (b)?
 

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