Chemistry What is the Molecular Weight of a Gas Using the Ideal Gas Law?

Thread starter gwiber
Start date Dec 6, 2011
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Molecular Molecular weight Weight

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To find the molecular weight (MW) of an unknown gas, the Ideal Gas Law (PV = nRT) is applied. Given a mass of 0.0097561 g, a volume of 0.2 L, a temperature of 500 K, and a pressure of 2 atm, the calculation yields an MW of 1 g/mol. The formula used for the calculation is mw = (mass * R * T) / (P * V). While the answer is confirmed as correct, showing the detailed steps of the calculation is recommended to identify any potential errors. Understanding the Ideal Gas Law is essential for determining the molecular weight of gases accurately.

Dec 6, 2011

gwiber

1. A 0.0097561 g quantity of an unknown gas occupies 0.2 L at 500 K and 2 atm. What is the Molecular Weight (MW) of the gas ?

2. PV = nRT

3. mw=0.0097561*0.082*500/2*0.2
mw=1

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Dec 6, 2011

ptolema

Your answer is right, although it would be nice to see some work shown in case there are any minor errors that could be caught.

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