What is the new pressure in a bicycle tire after riding on a hot day?

  • Thread starter Thread starter LeonJHardman
  • Start date Start date
  • Tags Tags
    Chem Pressure
AI Thread Summary
The discussion centers on calculating the new pressure in a bicycle tire after it heats up from 28°C to 58°C while riding. The initial tire pressure is 68 psi, and the volume increases by 3.9%. The user attempts to convert pressure to pascals and temperature to Kelvin, ultimately calculating a new pressure of 6.89 psi, which they doubt is correct. They are reminded that the relationship between pressure, volume, and temperature is governed by the ideal gas law, PV = nRT, but for this scenario, only P, V, and T are relevant. The conversation emphasizes the importance of correctly applying the ideal gas law to find the accurate new pressure.
LeonJHardman
Messages
6
Reaction score
0

Homework Statement


A bicycle tire is filled with air to a pressure of 68 psi, at a temperature of 28°C. Riding the bike on asphalt on a hot day increases the temperature of the tire to 58°C. The volume of the tire increases by 3.9%. What is the new pressure in the bicycle tire?



Homework Equations


PV=NRT


The Attempt at a Solution


Well... I went through it first by changing psi into pascals, then Celcius into Kelvin. then I made an attempt to find volume which I got 5.9736e-4 for. ( i kind of ignored the moles because I ddidn't know what to do with it, so I put it in as 1 to pretty much negate it) then I multiplied the volume by 1.039 and plugged in the R constant and 359.15 K to try to find pascals. which I got 47484.6921 Pascals, but it asked for answers in psi, so I tried to switch it to psi by dividing by 6894.8 and got 6.89 psi. I don't think this is even close to right.
 
Physics news on Phys.org
Your main quantities are P, V, T. The quantities of n and R are not needed. Neither of these last two would change. Do you remember how P, V, and T by themselves are related?
 
PV= T right?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
View full post »

Similar threads

Relationship Between Bicycle Tire Pressure and Speed
Replies
3
Views
2K
How Many Moles of Gas Are in the Bicycle Tire?
Replies
1
Views
15K
Bicycle tire width vs. pressure for identical comfort
Replies
8
Views
2K
Tire pressure changing due to temperature
Replies
25
Views
10K
How do I calculate the gauge pressure?
Replies
2
Views
5K
How to Solve an Ideal Gas Equation Problem with Changing Tire Pressures?
Replies
7
Views
2K
What Is the Coefficient of Rolling Friction for a Low-Pressure Bicycle Tire?
Replies
2
Views
13K
Pumping Bicycle tire: Find volume, work done, temperature
Replies
8
Views
6K
Gauge Pressure of Tire After Driving
Replies
1
Views
8K
Calculate Tire Pressure After Compression & Heating
Replies
15
Views
4K

Hot Threads

Recent Insights

Back
Top