physicsgrouch
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A transverse, sinusoidal wave is traveling along a string. It moves in the negative x-direction, and it has an amplitude of 5 cm. At time t=0, the point at x=0 is at a displacement of 4 cm and is traveling upward. What is the phase angle in degrees?
x = A*cos(\omega*t+\phi)
At t=0, \omega*t = 0, so x = A*cos(\phi). Therefore, \phi = arccos(x/A) = arccos(.8) = 36.87.
The acceleration is negative and the velocity is positive, so the angle is 360 - 36.87 = 323.13 degrees, right?
Homework Equations
x = A*cos(\omega*t+\phi)
The Attempt at a Solution
At t=0, \omega*t = 0, so x = A*cos(\phi). Therefore, \phi = arccos(x/A) = arccos(.8) = 36.87.
The acceleration is negative and the velocity is positive, so the angle is 360 - 36.87 = 323.13 degrees, right?