Outrageous said:
The potential here is the surrounding of the particle? It is a condition for finding the wavefunction when the particle is in harmonic oscillator's potential surrounding?
We imagine the particle experiences a force from somewhere.
The potential describes how that force changes with the position of the particle without saying anything about what causes the force.
For infinite wall,ψ(0)=0 ,ψ(L)=0, L is the width of the well. Then what is the meaning when we says ψ(0)=0, is that mean there is no particle at x=0?
It means the amplitude of the wave-function is zero there. The wavefunction is totally abstract.
If the wavefunction square doesn't give the probability of anything, then why is ψ(0)=0 correct?
Because that way it will be a solution to the Schrodinger Equation. Because that is how wave-functions behave if they are to lead to physically meaningful results. It's still not a probability function.
The wavefunction itself does not give probabilities, but you can use it to construct the probability density function for position (see vanhees above). Do you know how probability density functions work?
The probability of finding the particle at a particular position x is
zero. The classical idea that a particle may occupy a particular position at a particular time is one of those ideas you have to give up.
You can only measure a position to be within some range of values.
The probability that the particle will be found between x=a and x=b : a<b is: $$P(a<x<b)=\int_a^b\psi^\star (x)\psi (x)\; \mathrm{d}x$$
Are you teaching yourself quantum mechanics or are you doing a course?