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Jade Falcon
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When I took physics I learned that cavendish measured the gravitational constant G (a so-called, “non-derivable constant”), by using a torsion balance to measure the attraction of two bodies. However, what exactly is G? Is it just there to make things "fit" or what? So some time ago I read a paper stating that G can be derived using plank units as a form of the quantum vacuum. Opinions? 
\delta_{ZP} = \frac{m_P}{l^3_P} = (2.177 x 10^(-8) kg) / (4.22 x 10^(-105) m^3 = 5.159 x 10^(96) kgm^(-3)
Where \delta_{ZP} = vacuum mass-density equivalent, m_P = Plank mass, and l^3 = V_P (Plank Volume).
By substituting G by the corresponding Plank unites, we get:
G = \frac{1}{\delta_{ZP} t^2_P}= 6.67 x 10^(-11) m^3 kg^(-1) s^(-2) !
Consequently, Newton's equation of gravitation adopts the following form by susbtituting G.
F = \frac{1}{\delta_{ZP} t^2_P} \frac{m_1 m_2}{d^2}
The paper can be found here http://www.journaloftheoretics.com/Articles/4-2/UGC-QE-final.pdf
\delta_{ZP} = \frac{m_P}{l^3_P} = (2.177 x 10^(-8) kg) / (4.22 x 10^(-105) m^3 = 5.159 x 10^(96) kgm^(-3)
Where \delta_{ZP} = vacuum mass-density equivalent, m_P = Plank mass, and l^3 = V_P (Plank Volume).
By substituting G by the corresponding Plank unites, we get:
G = \frac{1}{\delta_{ZP} t^2_P}= 6.67 x 10^(-11) m^3 kg^(-1) s^(-2) !
Consequently, Newton's equation of gravitation adopts the following form by susbtituting G.
F = \frac{1}{\delta_{ZP} t^2_P} \frac{m_1 m_2}{d^2}
The paper can be found here http://www.journaloftheoretics.com/Articles/4-2/UGC-QE-final.pdf
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