What is the position operator in the momentum basis for a given momentum value?

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SUMMARY

The position operator in the momentum basis for a given momentum value is defined by the equation = i\hbar\frac{d}{dp'}\delta{p-p'}. This relationship is derived from the properties of Hermitian operators and involves the momentum representation of the position operator. The proof utilizes the integral transformation between position and momentum bases, specifically leveraging the delta function and the derivative with respect to momentum.

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Homework Statement



I need to prove that, <p'|\hat{x}p> = i\hbar\frac{d}{dp'}\delta{p-p'}

i.e. find the position operator in the momentum basis p for p'...

It's easy to prove that <x'|\hat{x}x> = <\hat{x}x'|x> = x'<x'|x> = x'\delta{x-x'}
(position operator in position basis for x')
since I can use the fact that the operator x is hermitian. But what about for the first problem? Any hints?
 
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<p'|X|p> = int_x dx <p'|X|x><x|p> = int_x dx x <p'|x> <x|p> = int_x dx x (1/√2πhbar) e-ixp/hbar <x|p> =-hbar/i int_x dx ∂/∂p' <p'|x> <x|p> = ihbar ∂/∂p' ... = what you need.
 
Great. Thanks so much.
 

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