What Is the Power Developed by a Boat Overcoming Drag?

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A boat moving at constant speed v through still water faces a total frictional drag F. The power developed by the boat to overcome this drag is correctly calculated as Fv, not 1/2Fv. The confusion arises from misunderstanding the relationship between drag and the force required to maintain speed; the total drag F must be countered by an equal force to achieve constant velocity. The discussion emphasizes that drag and resistance are equivalent in this context, leading to the conclusion that the power needed is directly proportional to the drag force and speed. Thus, the correct answer is Fv, clarifying the misconception regarding the use of 1/2Fv.
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Homework Statement


A boat moving at constant speed v through still water experiences a total frictional drag F.
What is the power developed by the boat?
a) 1/2Fv b) Fv

The Attempt at a Solution


I know the correct answer is b. My confusion is why is a incorrect?
My reasoning: The boat experiences a total drag of F. Which means at every point the boat experiences a resistance where R < F. Thus to steer at v, we have to apply a force of R. Which will provide the only option 1/2Fv.
 
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What exactly happens at every point between the boat and the water is a big story of fluid dynamics I doubt we want to discuss for this specific problem. There will be an infinitesimal force ##dF_i## at every point and the sum(more accurately the integral) of all these forces will be ##\vec{F}+\vec{A}=\sum \vec{dF_i}## , where A is the buoyancy force which is canceled by the weight of the boat. So all that is left is the force F. So we have to supply a force equal and opposite to F to keep the boat move at constant speed v. If you do the math (starting from the definition of the power and also using the definition of work of a force) for a constant force applied at a body that moves with constant velocity v, the power provided by force F is equal to Fv.
 
Last edited:
Faiq said:
I know the correct answer is b. My confusion is why is a incorrect?
My reasoning: The boat experiences a total drag of F. Which means at every point the boat experiences a resistance where R = F. Thus to steer at v, we have to apply a force of R. Which will provide the only option 1/2Fv.
Drag and resistance are the same thing!
 
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