What is the ppm concentration of an aqueous solution with 0.0050% Ag+ ions?

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The discussion focuses on calculating the ppm concentration of an aqueous solution with 0.0050% Ag+ ions. The initial calculation attempts to convert the percentage into grams, assuming a 1 L solution, resulting in 0.00005 g of Ag+ ions. There is confusion regarding the conversion to ppm, with one participant questioning the steps and the meaning of the percentage notation. Clarification is sought on the mass of the solution and the implications of the calculated values. The conversation highlights the need for clear understanding of units and conversions in chemistry.
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Homework Statement


An aqueous solution is found to be 0.0050% Ag+ ions. Calculate the ppm concentration of the solution.

Homework Equations


1mg / 1 L

The Attempt at a Solution


0.0050%/100 = 0.00005g
Assuming there is 1 L of solution

.00005g *(1/1000)

0.00000005 mg/L

1mg/L = 1 ppm

0.00000005 ppm
 
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Hi brycenrg:

I don't understand your attempt at a solution. Can you explain the steps?

I also don't understand the notation: 0.0050% Ag% ions. What do the percent signs mean?

Regards,
Buzz
 
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The percent is the amount of Ag ions of the whole solution, pretty sure
 
brycenrg said:
0.0050%/100 = 0.00005g

Doesn't make much sense to me. Where did the g come from? Is it 0.00005g in 1 L, in 100 L, in any volume?

You are right about assuming 1 L of a solution. What would be its approximate mass?
 
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