What is the Probability Density for a Wave Function?

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SUMMARY

The discussion centers on normalizing the wave function ψ = A(eix + e-ix) in the interval -π < x < π and calculating the probability of finding a particle in specific ranges. The normalization process yields A = √(1/4π). Participants clarify that the probability density is calculated using the integral of the product of the wave function and its complex conjugate, ψψ*. Additionally, it is emphasized that the results can be expressed in terms of real trigonometric functions, eliminating the imaginary unit i from the final probability calculations.

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  • Understanding of wave functions in quantum mechanics
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aglo6509
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Homework Statement


A wave function ψ is A(eix+e-ix) in the region -π<x<π and zero elsewhere. Normalize the wave function and find the probability of the particle being (a) between x=0 and x=π/8, and (b) between x=0 and x=π/4.

Homework Equations





The Attempt at a Solution



So to normalize the function, I multiplied it by its complex conjugate (A(e-ix+eix) and got:
∫A2[(eix+e-ix)(e-ix+eix)dx=1 From -π to π
∫2A2dx=1
2A2x(from -π to π)=1
2A2π+2A2π=1
4A2π=1

A=sqrt(1/4π)

Now that I have the function normalized, I can find the probability the question asks for. The problem I'm having is however do you take the integral of complex numbers the same way as a real number?

The best attempt I can get is:
∫(sqrt(1/4π)(eix+e-ix)dx From 0 to π/8
(sqrt(1/4π))∫(eix+e-ix)dx
(sqrt(1/4π))(ieix-ie-ix)

Would I now just plug in 0 and π/8 and leave my answers in terms of i?

Thanks for taking the time to look at this.
Aglo6509
 
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Hi aglo,

The probability density is ψψ* ("*" for complex conjugate). The wave function can be complex, but probability can not!

ehild
 
Last edited:
It might be helpful for you if you note that
\frac{e^{ix}+e^{-ix}}{2} = Cos(x)
so your answers won't even involve any i since those trig functions are real!

also, the density you're looking for is \int \psi ^* \psi dx
 

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