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I am conviced that the answer provided in the key is wrong:
What is the probability of drawing 2 or 3 jacks from a standard deck of cards without replacement.
P(3jacks or 2jacks) = P(3jacks) + P(2jacks)
= P(J)P(J|J)P(J|(J|J)) + P(J)P(J|J)*(3!/2!)
= 1/5525 + 72/5525
= 73/5525 != 0.217
What am I doing wrong? And 0.217 seems absurdly high.
What is the probability of drawing 2 or 3 jacks from a standard deck of cards without replacement.
P(3jacks or 2jacks) = P(3jacks) + P(2jacks)
= P(J)P(J|J)P(J|(J|J)) + P(J)P(J|J)*(3!/2!)
= 1/5525 + 72/5525
= 73/5525 != 0.217
What am I doing wrong? And 0.217 seems absurdly high.
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