What Is the Probability of Guessing Correctly on a Mixed Multiple Choice Test?

Click For Summary
SUMMARY

The probability of a student correctly guessing answers on a mixed multiple choice test with 12 questions—8 having 4 options each and 4 having 5 options each—was calculated. The student needs to get exactly 2 of the 4-option questions correct and at least 3 of the 5-option questions correct. The calculations showed that the probability of getting exactly two of the eight four-option questions correct is 0.3115, while the probability of getting at least three of the four five-option questions correct is 0.0272. The combined probability, however, was incorrectly stated as 0.2552, indicating a potential misinterpretation of the problem's requirements.

PREREQUISITES
  • Understanding of combinatorial mathematics (binomial coefficients)
  • Knowledge of probability theory, specifically independent events
  • Familiarity with the binomial probability formula
  • Basic skills in statistical analysis
NEXT STEPS
  • Study the binomial probability formula for independent events
  • Learn about combinatorial calculations, specifically binomial coefficients
  • Explore examples of mixed multiple choice probability problems
  • Investigate common pitfalls in interpreting probability questions
USEFUL FOR

Students, educators, and statisticians interested in probability theory, particularly those working with multiple choice assessments and combinatorial problems.

skhan
Messages
2
Reaction score
0
A multiple choice test contains 12 questions, 8 of which have 4 answers each to choose from and 4 of which have 5 answers to choose from. If a student randomly guesses all of his answers, what is the probability that he will get exactly 2 of the 4 answer questions correct and at least 3 of the 5 answer questions correct?
ANS: 0.2552

Heres what I did:

Out of the 8-four answer questions, the student gets 2 of them = (8C2)
Out of the 4-five answer questions, the student gets 3 of them = (4C3)

Therefore:

[8C2(.25)^2(.75)^6][ 4C3(.2)^3(.8)^1+ 4C4(.2)^4(.8)^0].

So:

The probability of getting exactly two of the eight four-option questions is 0.31146240234375.

The probability of getting at least three of the four five-option questions is 0.0272.

Those two are clearly independent. The product of those probabilities is 0.00847177734375.

BUT...the answer is suppose to be 0.2552 apparently.

Any input?
 
Physics news on Phys.org
Your method for this question seems right. All that I've found is that maybe the question was not written correctly. The answer given corresponds exactly for the situation where the student guesses exactly two questions from the first set (4 options) and at most 1 from the second set (5 options). This would mean having 2 correct guesses from the first set but not more than 3 correct answers overall. Hope this helped
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
5
Views
3K
Replies
3
Views
3K
  • · Replies 53 ·
2
Replies
53
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K