What is the probability of two seeds germinating if their types are unknown?

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The discussion focuses on calculating the germination probabilities of two seeds when their types are unknown. For two seeds of the same kind, the probability of both germinating is expressed as P = (Pa^2 + Pb^2)/2. When considering a scenario where two seeds are planted without noting their types, the probability that both are of type A given that both germinate is calculated using Bayes' theorem. The final formula derived for this probability is P(A|2 germinate) = Pa^2 / (Pa^2 + Pb^2). The thread emphasizes the importance of understanding these probabilities in seed germination scenarios.
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Let the germination probability (the probability that a seed sprouts) for seed A be Pa and B be Pb.


a) You plant two seeds of the same kind. If you turn heads or tails of what sort you plantet, what is the probability that 2 seeds germinate?
b) A student plant 2 seeds, but he had forgotten to note what sort of seed he had planted. What is the probability that it was A if both germinate?

What i think i right so far:

a) probability should be: P = (Pa^2+Pb^2)/2
 
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b) P(A|2 germinate)
=P(2 germinate|A)P(A)/P(2 germinate)
=\frac{\frac12P_a^2}{\frac12(P_a^2+P_b^2)}=\frac{P_a^2}{P_a^2+P_b^2}.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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