What is the process for differentiating y=e^x and y=lnx?

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The differentiation process for the functions y=e^x and y=lnx is straightforward. For y=e^x, the derivative is y' = e^x, indicating that the exponential function is its own derivative. For y=lnx, the derivative is y' = 1/x, which is valid for x > 0. Proper notation is crucial; stating "y = ln x = 1/x" is incorrect; instead, it should be expressed as "if y = ln x, then y' = 1/x."

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please explain in more detail on how we come up with the answers below. Thanks in advance!
(formulas much appreciated)

Differentiate:
  1. 1
    y=e^x
    =e^x

  1. 2
    y=lnx
    =1/x
 
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JasonX said:
please explain in more detail on how we come up with the answers below. Thanks in advance!
(formulas much appreciated)

Differentiate:
  1. 1
    y=e^x
    =e^x

  1. 2
    y=lnx
    =1/x


You should be careful of the notation you use. y = ln x = 1/x isn't true. You would be more correct in saying that if y = ln x, then y' = 1/x. Just thought id point that out.
 
yes good observation danago
 

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