- #1
joej
- 29
- 0
this should probably go in the HS section since it is review of some material covered there but... I'm guessing the same peole brose the two forums so I might as well post it here since it came up in college.
now the questions seems quite straight forward:
for a particle of mass m and charge q, moving in a circular path in a magnetic field B, show that its kinetic energe is proportional to the square of the radius of curvature of its path.
so we have:
r = (mv^2)/qvB
r = mv^2/F
F = ma
F = m((v^2)/r)
r = (mv^2)/(m((v^2)/r))
now... it all evens out and I'm stuck with nothing... could someon tell me where I'm going wrong with this
now the questions seems quite straight forward:
for a particle of mass m and charge q, moving in a circular path in a magnetic field B, show that its kinetic energe is proportional to the square of the radius of curvature of its path.
so we have:
r = (mv^2)/qvB
r = mv^2/F
F = ma
F = m((v^2)/r)
r = (mv^2)/(m((v^2)/r))
now... it all evens out and I'm stuck with nothing... could someon tell me where I'm going wrong with this