What is the proportionality constant for the Sun's gravitational force?

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The gravitational pull of the Sun on a planet is proportional to the planet's mass divided by the square of its orbital radius. The relevant formula is F_g = G(M_sun * M_planet) / r_orbit^2, where G is the gravitational constant, approximately 6.673e-11. For objects in orbit, the gravitational force is balanced by the centrifugal force due to their motion. This relationship highlights the dynamics of celestial mechanics. Understanding these forces is crucial for studying planetary orbits.
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This book that I'm reading mentions something where the gravitational pull of the Sun is proportional to that planet's mass/its orbital radius. What is this proportionality constant?
 
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Not quite , for an object in orbit the centrifugal force throwing it outwards is equal to the gravitational force pulling it into the object in the centre.
 
Oh, okay. So really, F=(4pi^2mr)/T2 should be used.
 
moonman239 said:
This book that I'm reading mentions something where the gravitational pull of the Sun is proportional to that planet's mass/its orbital radius. What is this proportionality constant?

The gravitational pull on any planet by the Sun is proportional to that planet's mass divided by the square of its orbital radius. The actual formula is

F_g = G\frac{M_{sun}M_{planet}}{r_{orbit}^2}

where G is the gravitational constant and is equal to 6.673e-11 when M is measured in Kg and r in meters.
 
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