What is the Q-value of the β- decay of Ni-65?

  • Thread starter Thread starter richphys
  • Start date Start date
  • Tags Tags
    Decay
richphys
Messages
17
Reaction score
0

Homework Statement



Using the atomic masses of 65Ni and 65Cu, calculate the Q-value of the β- decay of 65Ni (in MeV).
Answer = c) 2.14 MeV

Homework Equations



65Ni -> 65Cu + e-

The Attempt at a Solution



64.9308 -> 64.9277 + 0.0005485
Products - Reactants
-0.0025515 * 931.5 = 2.3767

My answer is in the same ball park but not correct. Are my equations correct?
 
Physics news on Phys.org
edited
 
Last edited:
Please put units into your attempt.
 
Also, assuming your masses are in atomic mass units, you have used the wrong mass for Ni-65.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top