What is the Quiescent Operating Point for FET's?

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SUMMARY

The Quiescent Operating Point (Q-point) for Field Effect Transistors (FETs) is not necessary when operating transistors as switches, such as BJTs or FETs, since they are typically biased OFF and turned ON by pulses. The Q-point is crucial only when the device is used as a linear amplifier to avoid distortion. For BJTs, ensuring operation in the saturation region is essential, which can be confirmed by the condition Ic = β * Ib > Vcc/Rc. Additionally, the DC sweep analysis is important for understanding the current and voltage behavior in switching circuits.

PREREQUISITES
  • Understanding of FET and BJT operation principles
  • Knowledge of biasing techniques for transistors
  • Familiarity with DC sweep analysis in circuit design
  • Basic concepts of saturation region in BJTs
NEXT STEPS
  • Study the calculation methods for DC sweep analysis in transistor circuits
  • Learn about biasing techniques for BJTs and FETs in linear amplifiers
  • Explore the characteristics of saturation region operation in BJTs
  • Investigate the impact of capacitance values on switching speed in CMOS inverters
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Electrical engineers, circuit designers, and students studying transistor applications in switching and amplification circuits will benefit from this discussion.

Physicslearner500039
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Hi All,

I was learning a lot of how to calculate the Quiescent operating point for FET's. But suddenly I got this doubt that if i am operating any transistor (BJT, FET) as a switch then I need not calculate the Q - point. Am I correct in this? Only when some AC signal is applied to avoid distortion I need to calculate the Q point?

Thanks in advance,
Regards,
Satya
 
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Calculate dc sweep if switching is not very fast.
 
satya77 said:
Hi All,

I was learning a lot of how to calculate the Quiescent operating point for FET's. But suddenly I got this doubt that if i am operating any transistor (BJT, FET) as a switch then I need not calculate the Q - point. Am I correct in this? Only when some AC signal is applied to avoid distortion I need to calculate the Q point?

Thanks in advance,
Regards,
Satya

Yes, you are right. The FET or BJT used as a switch would normally be biased OFF so the device can be turned ON by the pulses that drive the switch.

If you used the device as a linear amplfier, you arrange the biasing to avoid distortion in the output, but this is not done when the device is used as a switch.
 
Kholdstare said:
Calculate dc sweep if switching is not very fast.

I am sorry I did not understand what you said, for me when browsed for dc sweep is the calculation of currents and voltages, am i correct in this? how to know if the switching is fast or not ? Could you please explain me?

Thanks in advance,
Regards,
Satya
 
If you design the switch you don't need to calculate any Q point.
When BJT work as a switch this means that hi work on the saturation region.
So all you need to do is to ensure that BJT is in saturation region.
And simply if we ensure that
Ic = β * Ib > Vcc/Rc the the BJT is in saturation region.
So for a given Rc we need Rb smaller then

Rb ≤ (Vin - Vbe)/(Vcc - Vce(sat)) *βmin/K * Rc

Where
K is a overdrive factor, typical from 2 to 5.

Or even simpler rules
Ensure that
Ic/Ib = 50...10
 
satya77 said:
I am sorry I did not understand what you said, for me when browsed for dc sweep is the calculation of currents and voltages, am i correct in this? how to know if the switching is fast or not ? Could you please explain me?

Thanks in advance,
Regards,
Satya

Do you have any idea of dc sweep of CMOS inverters? You BJT/FET switching circuit can be simulated like that. FYI, dc sweep is varying the dc value of input voltage and looking at the voltage and currents in the circuit.

There are capacitance values provided in the datasheet of the component. From there you can have an idea of range of operating frequency.
 

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