What is the relationship between force and potential energy in elastic systems?

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The discussion focuses on understanding the relationship between force and potential energy in elastic systems, specifically in the context of Hooke's law. It highlights the need to calculate average force when determining work done by a spring, as the spring force is not constant but varies linearly. The average force during stretching is derived as F_average = kx/2, which simplifies the calculation of work done. The potential energy is represented as the area under the force versus displacement curve, prompting a comparison with a constant force that would yield the same area. This explanation emphasizes the significance of average force in the work-energy theorem for elastic potential energy.
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Who can explain me why we need to find an average force in proving theorem work=elastic potensial energy?
 
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If elastic potential energy (lets call it U) is the only energy involved, then W = - U. Remember, in using Hookes law, that if W = force times distance, the spring force is not constant, so you need to use calculus to find the work, or simply note that the spring force varies from 0 to its max value of kx.
 
I do not know calculus so please can someone explaın me wıthout usıng calculus
 
If the initial force in the spring is 0, and the force varies linearly with x (F=kx) as it is stretched, then at its maximum point of stretch , the force is F=kx, where x is at its maximum. So the average force during that period of stretch is just (0 + kx)/2, or F_average =kx/2. Now use that value of force in your work equation to find the work done by the spring.
 
On the graph of F vs. x, the potential energy is equal to the area under the curve between 0 and x. What constant force would have the same area underneath?
 
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