What is the relationship between speed and radius for a car to avoid skidding?

AI Thread Summary
The relationship between speed and radius for a car to avoid skidding is based on the equation f = mV²/R, where the centripetal force is provided by static friction. When a car's speed is doubled, the velocity squared becomes four times greater, necessitating a radius that is four times larger to prevent skidding. This means that if a car can round a curve of radius R at speed v without skidding, it can only round a curve of radius 4R at speed 2v. The maximum static friction remains constant, which is crucial for maintaining control. Understanding this relationship is key to safe driving on curves.
Jeann25
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If a certain car, going with speed v, rounds a level curve with a radius R, it is just on the verge of skidding. If its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:

Answer is 4R.. but I don't understand why?

I know the equation is f = mV²/R
 
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in the equation, the velocity is squared.

if the velocity becomes 2V, when you square it, it becomes 4V^2. to keep the car from skidding, the radius now has to change to 4r
 
Also, it is important to understand that the static friction, the source of the net centripetal force, is at its maximum value, and does not change.
 
I get it now. Thank you! :smile:
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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