What is the relationship between sup of unbounded sets in real numbers?

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1. sup (empty set) = -infinity, and if V is not bounded above, then sup V = +infinity. Prove if V\subseteqW\subseteqReal Numbers then sup V is lessthan/equalto supW




3. I used a proof by contrapositive, but I'm not sure if it is completely valid...
 
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I am assuming that these are intevals. You know that the lemma is clear if V=W, don't you? So assume that
<br /> V\subset W<br /> [\tex]<br /> So there is an element w in W which is not an element of V, examine |w-sup(V)|.
 
No reason to assume these are intervals.

Yes, the contrapositive is the way to go. Suppose sup(W)> sup(V). Then there exist x such that sup(V)< x< sup(W). From that it follows that there exist a member of W larger than x and so larger than any member of V, a contradiction.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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