What is the relationship between thrust and density in a half-submerged object?

  • Thread starter Thread starter nokia8650
  • Start date Start date
AI Thread Summary
The discussion revolves around understanding the relationship between thrust and density for a half-submerged object. Participants emphasize the importance of knowing how much water the object displaces, as this is crucial for calculating buoyancy and thrust. The significance of the object being half submerged is highlighted, indicating that it affects the amount of water displaced and, consequently, the thrust experienced. The conversation encourages sharing initial thoughts or attempts to solve the problem for more effective assistance. Overall, the focus is on grasping the fundamental principles of buoyancy in relation to density and displacement.
nokia8650
Messages
216
Reaction score
0
Last edited by a moderator:
Physics news on Phys.org
Hi nokia8650!

Show us what you've tried, and where you're stuck, and then we'll know how to help. :smile:

(and it would help us if you would type the question, instead of making us look at a picture of the words)
 
Thanks for the reply. I don't really know where to start - Iv never come across a problem like this! Il bear that in mind in future!

Thanks!
 
What is the significance of it being half submerged?

Thanks
 
nokia8650 said:
What is the significance of it being half submerged?

Thanks

It is floating, and the question tells you how much water it is displacing.

And that tells you … ? :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top