What is the relationship of modulus and temperature?

pipibaby
Messages
2
Reaction score
0
the reasons:
1. For low molecular weight materials, modulus drops rapidly with increasing temperature.

2. For High molecular weight amorphous materials, modulus drops to a secondary plateau region called the rubbery plateau (polymer entanglement prevents chain slippage). With further increase temperature, the modulus drops rapidly again. This point makes the viscous flow region.

3. For Semicrystalline polymers, the behavior is similar to high-molecular weight amorphous polymers, except that the modulus in the secondary plateau is normally higher because of
the restriction of crystalline regions for movement. At Tm, the crystalline region melts and the modulus drops in the viscous-flow region.
 
Physics news on Phys.org
Do you mean the bulk modulus?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top