What is the relationship of this formula?

AI Thread Summary
The formula E = I/r^2 represents the inverse square law of electromagnetic propagation, indicating that as the distance (r) from a light source increases, the intensity (E) decreases significantly, affecting the current produced by a photovoltaic cell. In experiments, luminance is directly proportional to the current generated by the cell, meaning that greater distance results in lower current readings. The discussion raises the question of whether the same setup can be used to measure illuminance at different angles, as the current output varies when the cell is not perpendicular to the light source. Adjustments to the micro ammeter could potentially allow for consistent current readings proportional to illuminance, regardless of the cell's angle. Overall, the relationship between distance, angle, and current output in photovoltaic applications is central to understanding the efficiency of light detection.
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E(lux), I (candelas) , r(meters)
E=I/r^2.


What is this formula ? I got it from a photovoltaic cell experiment. Use solar cell connect to a micro ammeter to detect the current produced due to the intensity of the light source.
The bigger the r , the lower the current.
how does the formula relate to current??


Please guide. Thank you.
 
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Basically that is a representation of the inverse square law of EM propagation. Each doubling of your distance from source equates to a four fold decrease in intensity.
 
In the photovoltaic cell experiment , the E is luminance or normal illuminance which is directly proportional to the current produced by the photovoltaic cell?

Is that possible to use the same set up to detect the illuminance by having same changes to the micro ammeter used? I mean when the cell is not normal to the light source, then the current gained is not same as the current gained when the cell is normal to the light source. My question is no matter the cell surface move with any angle, is that possible to get the reading of current which is directly proportional to the illuminance by doing something to the micro ammeter Thank you so much
 
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