What is the relative velocity of two cars traveling in the same direction?

AI Thread Summary
Two cars, A and B, are traveling in the same direction, with A initially 186 meters behind B. Car A travels at 24.4 m/s, while car B travels at 18.6 m/s, leading to a relative velocity of 5.8 m/s when calculating the time for A to catch B. Using the equation 186m = (5.8 m/s)t, it is determined that A will catch B in 32.1 seconds. The discussion also clarifies that relative velocity is calculated as the difference in speeds when the objects move in the same direction, contrasting with the addition of speeds when they move in opposite directions. The final answer confirms that A will catch B after 32.1 seconds.
mslena79
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Homework Statement


Two cars, A and B, are traveling in the same direction, although car A is 186m behind car B. The speed of A is 24.4m/s, and the speed of B is 18.6m/s. how much time does it take for A to catch B?



Homework Equations


Va+Vb=Vab, x=1/2(V0x+Vx)t


The Attempt at a Solution



Va=24.4 m/s, Vb=18.6m/s, Vab=43.0m/s,
186m=1/2(24.4m/s+43.0m/s)t
t=5.52s, Just not sure if this is right!
 
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No it isn't right... I don't understand the equations:

Va+Vb=Vab, x=1/2(V0x+Vx)t

how are you getting them?

you can just get the equation for the position for car B as a function of time... get the equation for car A... and set them equal.

You can also do it with relative velocity... in which case

186 = (velocity of A with respect to B)*t
 
for relative velocity, velocity of A with respect to B is Va+Vb=Vab (24.4m/s+18.6m/s=43.0m/s).
186m=(43.0 m/s)*t
t=4.33s
 
mslena79 said:
for relative velocity, velocity of A with respect to B is Va+Vb=Vab (24.4m/s+18.6m/s=43.0m/s).
186m=(43.0 m/s)*t
t=4.33s

Relative velocity is the difference, not the sum of the two velocities.
 
Oh, it is not clear from my text. So, (24.4m/s-18.6m/s=5.8m/s)
186m=(5.8m/s)t
t=32.1s
 
mslena79 said:
Oh, it is not clear from my text. So, (24.4m/s-18.6m/s=5.8m/s)
186m=(5.8m/s)t
t=32.1s

yup. that's right.
 
thanks, the textbooks never have examples like the ones you have to do in the homework, it makes it very difficult.
 
mslena79 said:
thanks, the textbooks never have examples like the ones you have to do in the homework, it makes it very difficult.

One thing I wanted to mention, if the two cars were going in opposite directions, this this is what would happen... if we take east as positive, west as negative... let's say A is going east. And B is going west. So A's velocity is 24.4m/s B's velocity is -18.6m/s. So A's velocity with respect to B is (24.4 - (-18.6)) = 43m/s... so if they were going in opposite directions, the numbers add... And then you'd get 4.33s like you did before...

But yeah, for your question the answer is 32.1s, since they're going in the same direction.
 
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