What is the residue of f(z) = e^(-2/z^2) using a laurent series?

[cragar]

Homework Statement

Use a laurent series to find the indicated residue
f(z)=e^{\frac{-2}{z^2}}

Homework Equations

The Attempt at a Solution

So I expand the series as
follows 1-\frac{2}{z^2}+\frac{2}{z^4} ...
my book says the residue is 0 , is this because there is no residue term ?
the a_{-1} term

 

[FactChecker]

Yes

 

[cragar]

ok just wanted to make sure