What is the rope tension calculation for assembling transmission tower sections?

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The discussion revolves around calculating the rope tension required for assembling transmission tower sections, specifically involving a 4-tonne and a 7-meter high section. The user seeks assistance in determining the tension in the rope when adjusting the position of the sections using a Ute. Key calculations mentioned include the tension imposed on the rope, center of gravity, restraining load, and overturning moment. A rough diagram was requested to aid in the calculations, but it was not provided. The conversation emphasizes the importance of sharing information within the forum for collaborative support.
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Dear Friend,

I am working as Graduate Engineer in transmission line. We assemble and erect transmission tower. I am stuck in one calculation. I got two section of 4 tonne and 7 mt in height.To put this two section together . First section is lifted by crane and a 20 mm rope is attach to the top part of the section.This section is slowly bolted to the leg. we pull rope at 45 degree angle about 7 meter away from the bolted leg of the section to hold the section, rope is attach to the 2.5 tonne four wheel drive Ute. now we realize the chain of the crane so it can lift second section and bring close to the first section so both can bolted together. I need to calculate rope tension on the rope when rope is pulled forward and backward to adjust with second section so it can be bolted.( Note: Rope is attach to Ute, so basically Ute is moved forward and backward ) Please help me out so i can answer my boss. Waiting for reply.
 
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welcome to pf!

hi manish98982! welcome to pf! :smile:

it''s difficult to tell without seeing a diagram,

but if the only forces on the rod are its weight, the tension in the rope, and the force at the end of the rod where the pivot is,

then taking moments about the pivot, the tension times the distance from the pivot to the rope (measured perpendicularly to the rope) = the weight (mg) times the horizontal distance from the pivot to the centre of mass :wink:
 
hi manish98982! :smile:
manish98982 said:
Hi Tim,

Thanks for your reply. As per your request i have attach a rough diagram for you to the situation. please help me out in calculating

1) tension impose on rope due to section
2) center of gravity
3 restrain load impose on rope
4) overturning moment
5) Weather 16 mm polypropylene rope enough to hold restrain rope.Capacity of rope is 600 KN.

no, there's no diagram attached :redface:

can you provide a link to the diagram instead?

in future, please always reply on the thread, not by private message

and it's against forum rules for us to give out (or ask for) email addresses​
 

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