What is the rotation direction of a system with a force applied at point B?

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The discussion centers on determining the rotation direction of a system with forces applied at different points. The 400N component is confirmed to induce a counterclockwise rotation, while the 300N component, despite being above point A, causes a clockwise rotation due to its direction of force application. Torque calculations are suggested to determine which component has a greater effect on the overall rotation. By extending the lines of the forces to the axis, one can visualize their impact on rotation direction. Ultimately, the sign of the z component of the moment can be used to confirm the rotation direction.
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Hi, here is a system with a force acting on it. As you can see the force's components are shown. In systems like this, I can't decide in which direction the components rotate the system.

It is obvious that the 400N-component wants to rotate the system counter clockwise but what about the 300N-component?

Thanks!
 
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Faux Carnival said:
It is obvious that the 400N-component wants to rotate the system counter clockwise but what about the 300N-component?
Assuming point 'A' is your axis, the 300N-component 'wants' to rotate the system clockwise. Figure out the torque from each component--the bigger torque wins.

Or you can just extend the line of the 500N force back toward the axis and see on which side it falls. You'll see that the overall force acts to rotate the system counter-clockwise.
 
Thanks Doc. But I still can't tell why the 300N-component rotates it clockwise. Because it's above point A, it seems to me that it would rotate counter clockwise.
 
Faux Carnival said:
Thanks Doc. But I still can't tell why the 300N-component rotates it clockwise. Because it's above point A, it seems to me that it would rotate counter clockwise.
Extend the line of the 300N component all the way to the left. It's above point A but it acts to the right, thus rotating clockwise.
 
Let's say the force is applied at point B, you can calculate the moment at point A with the relation :
\overrightarrow{M_A}=\overrightarrow{AB} \wedge \overrightarrow{F}

Choosing the coordinate system such that x and y are respectively the horizontal and vertical axis, the sign of the z component of the moment will give you the rotation direction (i.e. counter clockwise is the z component is positive and clockwise if the z component is negative).

This is another way of telling how it rotates...
 
comparing a flat solar panel of area 2π r² and a hemisphere of the same area, the hemispherical solar panel would only occupy the area π r² of while the flat panel would occupy an entire 2π r² of land. wouldn't the hemispherical version have the same area of panel exposed to the sun, occupy less land space and can therefore increase the number of panels one land can have fitted? this would increase the power output proportionally as well. when I searched it up I wasn't satisfied with...

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