What is the significance of \hat{\theta} in polar vector coordinates?

AI Thread Summary
The discussion centers on the role of the unit vector \hat{\theta} in polar coordinates, questioning its necessity when a vector can be expressed as \textbf{r} = r \hat{\textbf{r}}. Participants argue that \hat{\textbf{r}} alone does not fully describe a vector since it depends on the angle \theta, which varies. The conversation highlights confusion about how vectors in polar coordinates relate to those in Cartesian coordinates and the physical interpretation of combining \hat{\textbf{r}} and \hat{\theta}. Ultimately, the significance of \hat{\theta} lies in its ability to represent directional changes in a two-dimensional plane, which is essential for accurately describing vectors in polar coordinates. Understanding this distinction is crucial for grasping the full representation of vectors in different coordinate systems.
ice109
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i don't understand the point of \hat{\theta} if a vector is completely described by \textbf{r}=r \hat{\textbf{r}}

btw tex is doing something weird, apparently i can't make greek letters bold
\textbf{\delta}
 
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no one of you math geniuses can answer this for me?
 
I don't pretend to be a math genius but perhaps none of them understands your question. What do you mean by "a vector is completely described by \textbf{r}=r \hat{\textbf{r}}". Are you talking about a specific vector? Because that certainly does not "completely describe" a general vector. If you have a vector "completely described" by \textbf{r}=r \hat{\textbf{r}} then you don't need \theta'.

If you have formulas for both r' and \theta', what makes you think that the vector is "completely described" by \textbf{r}=r \hat{\textbf{r}}
? Perhaps it would help if you stated the precise problem.
 
\hat{\textbf{r}}[/itex] depends on \theta... It changes according to the angle. Unless you know what \theta is you can't draw \hat{\textbf{r}}[/itex]
 
HallsofIvy said:
I don't pretend to be a math genius but perhaps none of them understands your question. What do you mean by "a vector is completely described by \textbf{r}=r \hat{\textbf{r}}". Are you talking about a specific vector? Because that certainly does not "completely describe" a general vector. If you have a vector "completely described" by \textbf{r}=r \hat{\textbf{r}} then you don't need \theta'.

If you have formulas for both r' and \theta', what makes you think that the vector is "completely described" by \textbf{r}=r \hat{\textbf{r}}
? Perhaps it would help if you stated the precise problem.

does \textbf{r} describe a general vector in cartesian coordinates? if it does then i don't see any difference between the position vector in cartesian coordinates and in polar coordinates.

in fact i don't even understand the physical meaning of a linear combination of \hat{\textbf{r}} and \hat{\theta}. actually that is erroneous , i have no problem visualizing the resultant of these two vectors, i would just need to connect them head to tail. what i don't understand is what i said before, what is the point of the \hat{\theta}}

the picture represents my understanding of the the polar coordinates in terms of the cartesian coordinates where \textbf{A} is the vector I'm trying to describe in terms of the the polar unit vectors. is it correct? and if it is correct why can't describe \textbf{A} by just scaling the \hat{\textbf{r}} a little and making its \theta argument little bigger?
 

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