What is the significance of the nonholonomity condition in General Relativity?

  • Context: Graduate 
  • Thread starter Thread starter samson
  • Start date Start date
  • Tags Tags
    Condition Gr
Click For Summary
SUMMARY

The significance of the nonholonomic condition in General Relativity revolves around the distinction between holonomic and nonholonomic bases. A nonholonomic basis, such as the unit radial vectors and orthogonal tangential vectors in polar coordinates (##r, \theta##), does not commute, which is essential for understanding the geometric structure of spacetime. In contrast, a holonomic basis allows for the selection of coordinates where basis vectors are represented as partial derivative operators (##\partial/\partial x^\mu##). This distinction is crucial for applications in differential geometry and the formulation of physical theories in curved spacetime.

PREREQUISITES
  • Understanding of General Relativity concepts
  • Familiarity with differential geometry
  • Knowledge of vector fields and dual vectors
  • Basic grasp of coordinate systems and their properties
NEXT STEPS
  • Study the implications of nonholonomic constraints in General Relativity
  • Explore Sean Carroll's lecture notes on differential geometry
  • Investigate the mathematical properties of holonomic and nonholonomic bases
  • Learn about the applications of nonholonomic systems in physics
USEFUL FOR

Students and researchers in theoretical physics, mathematicians specializing in differential geometry, and anyone interested in the geometric foundations of General Relativity.

samson
Hi everyone! Please what are the conditions necessary for space and time to be nonholonomic?
 
Physics news on Phys.org
To give a specific example. In polar coordinates, ##r, \theta##, a vector field that consists of unit radial vectors (often written as ##\hat{r}##), and orthogonal tangential vectors (often written as ##\hat{\theta}##) would be a non-holonomic basis. It might be more familiar in terms of the dual vectors (though the terminology might not be familiar, perhaps). dr and d##\theta## can be interpreted as dual vectors. Then dr and d##\theta## would be holonomic, and not normal (because the vectors don't have unit lengths). However, dr and ##r \, d\theta## would be non-holonmic, but normal, since the (dual) vectors do have unit length.

The notion of vectors as partial derivative operators and dual vectors gets some mention in Sean Caroll's lecture notes <<link>>, see for instance

In spacetime the simplest example of a dual vector is the gradient of a scalar function, the set of partial derivatives with respect to the spacetime coordinates, which we denote by “d”:

It's also worth looking up what a coordinate basis is. Note that "coordinate basis" is more or less just another term for "holonomic basis". (Perhaps some more mathematical sort will correct me if there is some tiny difference). If you look up "coordinate basis" in Caroll's lecture notes, you'll find that it's identified as being equiavalent to partial derivatives with respect to the coordaintes. So in our example a coordinate basis of vectors could be identified with partial derivative operators, such as ##\partial_r## or in different notation ##\frac{\partial}{\partial r}##. The identification of vectors as partial derivative operators is not very intuitive, but an important definition for differential geometry.
 
  • Like
Likes   Reactions: samson, vanhees71 and dextercioby
A holonomic basis is a basis where all of the basis vectors commute. Given a holonomic basis, it is possible to choose coordinates ##x^\mu## such that the basis vectors are the set of partial derivative operators ##\partial/\partial x^\mu##.
 
  • Like
Likes   Reactions: samson
samson said:
Hi everyone! Please what are the conditions necessary for space and time to be nonholonomic?
This is very helpful to me! Thanks for your time sir!
 
Ben Niehoff said:
A holonomic basis is a basis where all of the basis vectors commute. Given a holonomic basis, it is possible to choose coordinates ##x^\mu## such that the basis vectors are the set of partial derivative operators ##\partial/\partial x^\mu##.

Thanks sir
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 40 ·
2
Replies
40
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 62 ·
3
Replies
62
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K