What is the significance of the zero vector in a vector space?

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Discussion Overview

The discussion revolves around the significance of the zero vector in a specific vector space defined as V5 = {(x, 1) | x ∈ R}. Participants explore the concept of the zero vector, its role as an additive identity, and the implications of its definition within the context of this vector space.

Discussion Character

  • Conceptual clarification
  • Exploratory

Main Points Raised

  • One participant expresses confusion about why (0, 1) is considered the zero vector in the vector space V5, particularly due to the presence of the constant 1 in the y-coordinate.
  • Another participant clarifies that the zero vector is defined as the additive identity, meaning that for any vector (a, 1) in V5, the equation (a, 1) ⊕ (0, 1) = (a, 1) holds true.
  • A later reply acknowledges the clarification and emphasizes that the significance of the zero vector lies in its role as an additive identity rather than its numerical value.
  • One participant reflects on the nature of zero in the context of real numbers, suggesting that zero is defined by its properties within the field rather than its position on the real line.

Areas of Agreement / Disagreement

Participants generally agree on the definition of the zero vector as the additive identity, but there is some initial confusion regarding its representation in the specific vector space V5. The discussion remains exploratory, with participants refining their understanding rather than reaching a definitive conclusion.

Contextual Notes

Some assumptions about the properties of vector spaces and the nature of the zero vector may not be explicitly stated, leading to varying interpretations of the concept. The discussion does not resolve all uncertainties regarding the implications of the zero vector in this context.

74197
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Ok this is from a tutorial I am redoing again.

V5 = {(x, 1) | x ∈ R}, (x1, 1) ⊕ (x2, 1) := (x1 + x2, 1), c.(x, 1) := (cx, 1).

I understand that there exists a zero vector in this vector space, that comes in the form of (0,1). What I do not understand is why that is considered a zero vector for that vector space?

It is hard for me to 'see past' that 1 in the y-coordinate. Please ease my irritations, thank you :)
 
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74197 said:
Ok this is from a tutorial I am redoing again.

V5 = {(x, 1) | x ∈ R}, (x1, 1) ⊕ (x2, 1) := (x1 + x2, 1), c.(x, 1) := (cx, 1).

I understand that there exists a zero vector in this vector space, that comes in the form of (0,1). What I do not understand is why that is considered a zero vector for that vector space?

It is hard for me to 'see past' that 1 in the y-coordinate. Please ease my irritations, thank you :)



According to what you defined [tex]\forall (x,1)\in V5\,\,,\,\,(x,1)\oplus (0,1)=(0,1)\oplus (x,1)=(x,1)[/tex] and thus that is the zero vector in that set (supposedly, a vector space).

DonAntonio
 
The "zero vector" in any vector space, V, with vector addition [itex]\oplus[/itex] is the vector, a, such that, for any v in V, [itex]a\oplus v= v[/itex]. In other words, it is the "additive identity".

In this particular example, the "zero vector" is (0, 1): if v is any vector in this space, of the form (a, 1), then [itex](a, 1)\oplus (0, 1)= (a+0, 1)= (a, 1)=v[/itex].
 
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Ah...I see now. It's not about the 'zero', it's more about the fact that the zero vector makes for an additive identity. Thank you Don and HoI :)
 
74197 said:
Ah...I see now. It's not about the 'zero', it's more about the fact that the zero vector makes for an additive identity. Thank you Don and HoI :)

And if you think about it ... what makes the usual zero, "zero?" It's just that zero satisfies the properties of the zero element in the field of the real numbers. Other than that, it's just a point on the real line exactly like any other point.

That's what abstraction does ... it makes you see familiar things in a new way.
 

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