What is the significance of v=0 in Eddington-Finkelstein/Kerr coordinates?

[stevebd1]

v=0 in E&F/Kerr coordinates

Edit: I've realized the thread title is a bit misleading. The title suggests that v divided by u equals zero when in fact it's about the point where the ingoing and outgoing coordinates, v and u, become zero independently.
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Unless I've got something wrong, for static black holes, the ingoing null coordinates, v=t+r^\star, are v=∞ at large radii, -∞ at r_s, increasing back to zero inside the EH and becoming positive again before reducing back to zero at r=0

For non-static black holes, v=∞ at large radii, -∞ at r₊, ∞ at r_- and is finite at r=0; the opposite applies for outgoing null coordinates, u=t-r^\star (i.e. u=-∞ at large radii, ∞ at r₊, etc.).

As v moves from ∞ to -∞ and back again, there are points where v=0, for static black holes this is at ~2.218M and ~1.594M. This changes as spin is introduced, for a spin of a/M=0.95, v=0 occurs at ~1.934M and ~0.906M (in the case of u, for a spin of 0.95, u=0 occurs at ~3.859M and ~0.834M).

Is there a significance to these radii or is it just a coordinate issue? v=0 appears to be referred to as R₀ in this paper- http://www.damtp.cam.ac.uk/user/sg452/black.pdf pages 8 and 9.

 

[stevebd1]

One of the reasons I ask this is that the equation to reproduce the fallout from a radiative tail is-

m(v)=m_0-\delta m

where

\delta m=av^{-(p-1)}

In the case of a black hole, v would tend to zero outside the EH, meaning \delta m would blow up and m would become unbound.

This may have been discussed in http://arxiv.org/PS_cache/gr-qc/pdf/9403/9403019v1.pdf" where it's possibly referred to as the external potential barrier (page 4).

The same applies to the outflux equation at the Cauchy horizon-

m(v,r)\sim v^{-p}e^{\kappa_0\,v}\ \ \ \ \ \ (r<r_+)

simply being referred to as the potential barrier lying between the Cauchy horizon and event horizon (shallow region) where again, v (and u) tends to zero

In http://arxiv.org/PS_cache/gr-qc/pdf/0209/0209052v1.pdf" (page 14), though the equations are different, they seem to refer to something similar in the shallow region of a BH and even state it's related to u \rightarrow 0. While this appears to address the issue in the shallow region, m becoming unbound just outside the EH still seems unresolved when calculating the radiative tail.

 

[stevebd1]

According to http://www.faqs.org/faqs/astronomy/faq/part4/section-10.html", v=0 appears to be the 'surface of last influence'-

..light rays follow geodesics in spacetime. To describe things fully you need Eddington-Finkelstein coordinates. In these coordinates it's pretty easy to see there is a 'surface of last influence'. In fact, page 873 of MTW has a pretty good graphic showing just that. The surface of last influence is the 'birthpoint' of the black hole..

and http://www.sron.nl/~jheise/lectures/kruskal.pdf" (page 66)-

Figure 8.9 Surface of last influence. Spherical gravitational collapse is shown here in ingoing Eddington-Finkelstein coordinates. For each external particle or external observer there is a moment of the ”birth of the black hole”. The set of such moments form the ”surface of last influence”. Before passing this surface external observers can in principle still shine a flashlight onto the contracting star and receive the bounced light or he can collect a few baryons from the surface. After passing surface of last influence observers cannot interact (matter cannot be influenced) and can consider the object a black hole..

while this seems to justify the existence of v=0, it doesn't shed any light on the nature of the coordinate singularity that occurs in Price's power law \delta m=av^{-(p-1)} just outside the event horizon.

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UPDATE-
A number of links refer to v=0 as r₀, the peak of the potential barrier.

'..wave scattering on the peak of the potential barrier..'-
http://relativity.livingreviews.org/open?pubNo=lrr-1999-2&key=Chandra83 eq 30

A similar description applying to v=0 inside the event horizon, '..The radiation which crosses the event horizon gets scattered once again by the inner gravitational potential barrier..'-
http://arxiv.org/PS_cache/gr-qc/pdf/9805/9805008v1.pdf page 6 fig. 2

so it appears that v=0 isn't a coordinate singularity and has significance.