What Is the Smallest Integer d Such That a^d Equals 1 Mod n?

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Homework Statement


For any positive integer d and n, find the first integer d such that a^d =1 mod n

Homework Equations


Euler's totient function phi(n) = # of #s relatively prime to n
Will solve the condition if a and n are coprime but not for the first d

The Attempt at a Solution


If a and n are not coprime then there is no solution.
I am not sure how to find the smallest d such the condition holds. I know that d will be a factor of Euler's totient function.
 
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For any positive integer d and n, find the first integer d such that a^d =1 mod n
Is d given or is d to be found ? Is a arbitrary ? Or would the exercise have been something along the lines of
For any positive integer a and n, find the first integer d such that a^d =1 mod n
 
d is to be found. Essentially I want to find the smallest integer d such that a^d = 1 mod n holds true.
Yes, For any positive integer a and n, find the first integer d such that a^d =1 mod n is how the problem should have been stated.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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