What is the solution for (A^4)x with given eigenvectors and eigenvalues?

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Homework Statement


A is a 2x2 matrix with eigenvectors 1,-1 and 1,1 with respective eigenvalues 2 and 3. x is 2,0. Find (A^4)x


Homework Equations


I know (A^k)v=(lamda^k)v
But I just don't know how to solve this to find A and then multiple it by x

The Attempt at a Solution


See above

Thanks a lot for anyone's help or input!
 
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The eigenspace is two dimensional since there are two distince eigenvalues. Thus, A is diagonalizable. Then...
 
More simply, <2, 0>= <1, -1>+ <1, 1>. Apply A to that. You don't need to determine A itself.
 
You don't need to find A. (2,0)=(1,-1)+(1,1). How would you find A^4((1,-1))?
 
Ah I got it, (A^k)x=(lamda1^4)v1+(lamda2^4)v2

Thanks a lot for pointing out that those two vectors added up to x, I overlooked that. Would this be possible otherwise?
 
If the only information you have about A is it's eigenvectors, and you can't express the vector as a linear combination of eigenvectors, then, no, you don't have enough information about A.
 
Thank you very much you guys are awesome.
 
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