What Is the Specific Heat Capacity of Cream?

AI Thread Summary
The discussion revolves around calculating the specific heat capacity of cream based on the heat exchange with water in a silo. The water, initially at 90ºC, loses heat as it cools to 60ºC, resulting in a calculated heat loss of approximately -37,800 kJ. This heat is then used to raise the temperature of 250 kg of cream from 5ºC to 60ºC. The specific heat capacity of the cream is determined to be 2,749 J/kgºC. The calculations and approach taken are confirmed to be correct, although the user seeks validation of their results.
Priscilla
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Homework Statement



The cream is kept at 5 ºC in the lorries. It is pumped into silos, where it is pre-heated before being pasteurized. The silos are jacketed, and hot water is pumped through the jacket. Assuming no losses, if 300 kg of water at 90ºC enters the jacket and exits at 60 ºC, resulting in 250 kg of cream present in the silo being heated to 60oC, calculate:
a. The amount of heat lost by the water in the jacket of the silo.
b. The heat capacity of the cream
(Heat capacity of water is 4200 J/kg K)

Homework Equations



Q= mc(delta)T


The Attempt at a Solution



a) Q = (300kg)(4200J/kg ºC) (60ºC - 90ºC) = -3.78e4kJ
b) 3.78e4kJ = (250kg)(C)(60ºC - 5ºC)
C = 2749J/kgºC


I don't know if I did it right or not. Please check for me.
 
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I have not checked numbers, but approach is correct.
 
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