What is the Speed of a Transverse Wave on a Varying Thickness Wire?

[jlsoccer4]

Homework Statement

A wire that is 10 m long and has a uniform density(u) of 7.75 g/cm^3 is pulled to a tension of F=80 N. The wire, however, does not have a uniform thickness; rather, it varies uniformly from an initial radius of 1mm to a radius of 3mm where it is attached to a wall. If you send a wave pulse down the length of the string, how long does it take to reach the wall?

Homework Equations

v = sqrt(F/u)
u = m/L (m= mass, L= length)

The Attempt at a Solution

If I could find the volume of the wire, then I could determine the mass of the string, and the velocity of the pulse using the equations above. From there, once I had the velocity, since the units were m/s, I would divide by the distance to find the time it would take for the pulse to reach the wall. (Does this logic make sense?)

But how would I determine the volume?

 

[Fightfish]

That would be by integration.

 

[jlsoccer4]

What would the integration look like? Would the limits be from 1mm (.001m) to 3mm (.003m) and the integrand be pi*(r^2)*10m (volume of a cylinder)?

 

[Fightfish]

No. One method of how to obtain the integrand would be the classic "divide-and-conquer". We will divide the wire into infinitely many thin slices. We then consider the volume of each thin slice.

The volume of each thin slice would be \pi r^{2} dx. However, we realize also that the radius of each slice varies, and can be expressed as 0.01 + 0.002x, where x represents the distance of the slice from the starting point (taken to be the free end). So, we have the volume of each slice being \pi (0.01 + 0.002x)^{2} dx.

The total volume of the wire would thus simply be a summation of the volume of each slice across the entire length of the wire: \int^{10}_{0}\pi (0.01 + 0.002x)^{2} dx

 

[jlsoccer4]

Wouldn't r be equal to .001+.0002x (in terms of millimeters) and (1*10^-6) + (2*10^-7)x (in meters)? Since my limits are in meters, wouldn't my integrand need to be in the same units?

 

[Fightfish]

Oops, it should be r=0.001+0.0002x in terms of meters. Accidentally left off a factor of 10.
Why do you think that would be in milimeters?

 

[jlsoccer4]

I think that you are correct. I had my units mixed up. Thank you for the help on this problem, I truly appreciate it.

 

[bballman1441]

would this happen to be for a phys 132 class