What is the speed of the dart as it leaves the toy?

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The discussion revolves around calculating the speed of a rubber dart shot from a toy using a compressed spring. The relevant equations include the conversion of elastic potential energy (Ee) into kinetic energy (Ek). The spring's force constant is 3.5 x 10^2 N/m, and the spring is compressed 4.5 cm, which is crucial for the calculations. Participants confirm the correct formulas and emphasize the importance of using the compression distance in the energy equations. The final step involves solving for the dart's speed using the derived equations.
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Homework Statement



2. A child's toy shoots a rubber dart of mass 7.8g, using a compressed spring with a force constant of 3.5 x 10^2 N/m. The spring is initially compressed 4.5cm. All the elastic potential energy is converted into kinetic energy of the dart.
What is the speed of the dart as it leaves the toy?

Homework Equations


Ee = Ek
Ee = 1/2 k x^2
Ek = 1/2 mv^2

The Attempt at a Solution


Ee = Ek
1/2 (3.5 x10^2)(?) = 1/2 (.0078)v^2 ??
 
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In the equation for spring energy, x represents the distance the spring is compressed.
 
jbjohnybaker said:

Homework Statement



2. A child's toy shoots a rubber dart of mass 7.8g, using a compressed spring with a force constant of 3.5 x 10^2 N/m. The spring is initially compressed 4.5cm. All the elastic potential energy is converted into kinetic energy of the dart.
What is the speed of the dart as it leaves the toy?


Homework Equations


Ee = Ek
Ee = 1/2 k x^2
Ek = 1/2 mv^2

The Attempt at a Solution


Ee = Ek
1/2 (3.5 x10^2)(?) = 1/2 (.0078)v^2 ??



You got the formulas correctly
E= kinetic + potential
Einitial = E final
1/2 kx^2 + 1/2 mv^2 = 1/2 mv^2 + 1/2 kx^2

1/2 * 3.5 x 10^2 * .04m + 0 = 1/2 *.0078 kg v^2 +0

now just solve for V.
I think you just missed the information that tells you the compression (x)
 
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