What is the speed of two objects after a perfectly inelastic collision?

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In a perfectly inelastic collision, a 6 kg object moving at 9.9 m/s collides with a 19 kg object moving at 7.2 m/s at a 24-degree angle. The initial momentum in both x and y directions is calculated, leading to an equation for the final velocity of the combined mass. The first attempt at solving the problem yielded a final speed of approximately 8.07 m/s, but the user doubted its accuracy due to discrepancies in calculations. Feedback indicated that the original method was correct, and issues might stem from significant figure errors in the online homework system. The discussion clarified that while the final speed is determined, the direction of the combined object's velocity is not necessary for this specific problem.
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Homework Statement


A 6 kg object moving with a speed of 9.9 m/s collides with a 19 kg object moving with a velocity of 7.2 m/s in a direction 24* from the initial direction of motion of the 6 kg object. What is speed of the two objects after the collision if they remain stuck together?


Homework Equations



Px = m1v1icos\theta+m2v2icos\theta = m1v1fcos\theta + m2v2fcos\theta

Py = m1v1isin\theta+m2v2isin\theta = m1v1fsin\theta + m2v2fsin\theta

The Attempt at a Solution



Edit I realized my original way was faulty in its logic.

So what I did was I began by finding the initial and final momenta components in both the x and y directions for the two particles. Being that they stick together their final velocity ought to be the same.

\SigmaPxi = m1v1cos\theta + m2v2cos\theta

=184.37302

\SigmaPyi = m1v1sin\theta + m2v2sin\theta

=55.641573

As I mentioned their final velocity should be equal since they are stuck together. Equating my initial momenta to my final momenta in the x direction I get the following:

Vf = \frac{(m1v1cos\theta + m2v2cos\theta}{(m1+m2)cos\theta}

=8.072856 m/s

When I checked it using the momenta of the y direction I come to a different value for the final velocity which doesn't make sense so I know I made a mistake somewhere... Thanks in advance.

Joe



Edit: I tried a new way, but
 
Last edited:
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Looks good to me.
 
Thanks Doc Al, are you referring to the first way I solved the problem or referring to this edited version? The first way did not work, so that's why I tried a new method. Thanks for all your help in all of my posts.

Joe
 
Actually, your first attempt was the correct solution. How do you know the answer you got is wrong?
 
Agent M27 said:
Thanks Doc Al, are you referring to the first way I solved the problem or referring to this edited version? The first way did not work, so that's why I tried a new method.
I was referring to your original post, which looked fine to me. (I haven't looked at your revision.)
 
It is an online homework module, and this is not the first question that I have been correct about and it kicked back my answer as incorrect...Thanks for your assistance.

Joe
 
Thought so. Could be you're entering too many significant figures.
 
vela said:
Thought so. Could be you're entering too many significant figures.

Do you know the direction (angle) after collision?
 
inky said:
Do you know the direction (angle) after collision?
Why would that matter?
 
  • #10
Doc Al said:
Why would that matter?

I mean after collision, two objects stuck together. So velocities are the same but problem didn't mention direction is angle theta. I think angles are not the same before and after collision.
 
  • #11
inky said:
I mean after collision, two objects stuck together. So velocities are the same but problem didn't mention direction is angle theta. I think angles are not the same before and after collision.
True, but the direction of the final velocity doesn't matter for this problem. All they ask for is the speed.
 
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