What is the substitution rule for solving integrals with a radical expression?

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Homework Statement



as 0 goes to a [tex]\int \sqrt x_{a^2-x^2} \ {dx}[/tex]

Homework Equations



Substitution Rule

The Attempt at a Solution



I need help starting it, i don't understand at all
 
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You could try a trig substitution. Does anything come to mind?
 
sorry how do i put an x before the square root
its supposed to be there
 
If you get into tex problems then just say it in words, i.e. integral from 0 to a of x*sqrt(a^2-x^2)dx. Is that what you mean? In that case try the even simpler substitution of u=a^2-x^2.
 
Is this it?
[tex] \int_0^a x \sqrt{a^2-x^2} \ {dx} [/tex]
 
With that x dx, there is a very simple susbstitution.